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[ν”„λ‘œκ·Έλž˜λ¨ΈμŠ€ LV.1] μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜?

hyebin (Helia) 2023. 2. 7. 06:56
λ°˜μ‘ν˜•
ν”„λ‘œκ·Έλž˜λ¨ΈμŠ€ LV.1 λͺ¨μŒ

μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜?

문제 μ„€λͺ…

길이가 n이고, "μˆ˜λ°•μˆ˜λ°•μˆ˜λ°•μˆ˜...."와 같은 νŒ¨ν„΄μ„ μœ μ§€ν•˜λŠ” λ¬Έμžμ—΄μ„ λ¦¬ν„΄ν•˜λŠ” ν•¨μˆ˜, solution을 μ™„μ„±ν•˜μ„Έμš”. 예λ₯Ό λ“€μ–΄ n이 4이면 "μˆ˜λ°•μˆ˜λ°•"을 λ¦¬ν„΄ν•˜κ³  3이라면 "μˆ˜λ°•μˆ˜"λ₯Ό λ¦¬ν„΄ν•˜λ©΄ λ©λ‹ˆλ‹€.

μ œν•œ 사항

  • n은 κΈΈμ΄ 10,000 μ΄ν•˜μΈ μžμ—°μˆ˜μž…λ‹ˆλ‹€.

μž…μΆœλ ₯ 예

n return
3 "μˆ˜λ°•μˆ˜"
4 "μˆ˜λ°•μˆ˜λ°•"

제좜

func solution(_ n:Int) -> String {
    var re = ""
    
    for i in 1...n{
        if i % 2 == 1{
            re += "수"
        }
        else{
            re += "λ°•"
        }
    }
    return re
}
1λΆ€ν„° nκΉŒμ§€ λ°˜λ³΅λ¬Έμ„ μ‹€ν–‰ν•˜μ—¬, ν™€μˆ˜λΌλ©΄ "수" 짝수라면 "λ°•"을 re λ³€μˆ˜μ— μΆ”κ°€ν•œλ‹€.

λ‹€λ₯Έ 풀이

func solution(_ n:Int) -> String {
    return "\(String(repeating: "μˆ˜λ°•", count: n / 2))\(n % 2 == 0 ? "" : "수")"
}
"μˆ˜λ°•"을 n/2 만큼 λ°˜λ³΅ν•œ ν›„, n이 ν™€μˆ˜λΌλ©΄ "수"λ₯Ό 뒀에 μΆ”κ°€ν•œλ‹€.
λ°˜μ‘ν˜•