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[ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค LV.0] ๋ฌธ์ž ๋ฐ˜๋ณต ์ถœ๋ ฅํ•˜๊ธฐ

by hyebin (Helia) 2022. 12. 13.
๋ฐ˜์‘ํ˜•

๋ฌธ์ž ๋ฐ˜๋ณต ์ถœ๋ ฅํ•˜๊ธฐ

๋ฌธ์ œ ์„ค๋ช…

๋ฌธ์ž์—ด my_string๊ณผ ์ •์ˆ˜ n์ด ๋งค๊ฐœ๋ณ€์ˆ˜๋กœ ์ฃผ์–ด์งˆ ๋•Œ, my_string์— ๋“ค์–ด์žˆ๋Š” ๊ฐ ๋ฌธ์ž๋ฅผ n๋งŒํผ ๋ฐ˜๋ณตํ•œ ๋ฌธ์ž์—ด์„ return ํ•˜๋„๋ก solution ํ•จ์ˆ˜๋ฅผ ์™„์„ฑํ•ด๋ณด์„ธ์š”.

์ œํ•œ ์‚ฌํ•ญ

  • 2 ≤ my_string ๊ธธ์ด ≤ 5
  • 2 ≤ n ≤ 10
  • "my_string"์€ ์˜์–ด ๋Œ€์†Œ๋ฌธ์ž๋กœ ์ด๋ฃจ์–ด์ ธ ์žˆ์Šต๋‹ˆ๋‹ค.

์ž…์ถœ๋ ฅ ์˜ˆ

my_string n result
"hello" 3 "hhheeellllllooo"

์ž…์ถœ๋ ฅ ์˜ˆ ์„ค๋ช…

์ž…์ถœ๋ ฅ ์˜ˆ #1

  • "hello"์˜ ๊ฐ ๋ฌธ์ž๋ฅผ ์„ธ ๋ฒˆ์”ฉ ๋ฐ˜๋ณตํ•œ "hhheeellllllooo"๋ฅผ return ํ•ฉ๋‹ˆ๋‹ค.

์ œ์ถœ

import Foundation

func solution(_ my_string:String, _ n:Int) -> String {
    var answer = ""

    for s in my_string{
        answer += String(repeating: String(s), count: n)
    }

    return answer
}

 

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